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jasenka [17]
3 years ago
11

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t – 16t2. How long after launch d

oes the projectile return to the ground?
Mathematics
2 answers:
Phoenix [80]3 years ago
8 0

Answer:

A. 2 Seconds

Step-by-step explanation:

Just took it. Edg2020. Hope this helps :)

Ulleksa [173]3 years ago
5 0

Answer:

2

Step-by-step explanation:

when it return to the ground , h = 0

32t -16t2 = 0 and solve for t

t = 0, 2   ....0 is the start, 2 is when it returns

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Suppose a population grows according to the logistic equation but is subject to a constant total harvest rate of H. If N(t) is t
Elenna [48]

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a) Equilibrium point : [ 947, 53 ]

b) N = 947 is stable equilibrium, N = 53  is unstable equilibrium

c) N0, the population will not go extinct

Step-by-step explanation:

a)

Given that;

r = 2, k = 1000, H = 100

dN/dT = R(1 - N/k)N - H

so we substitute

dN/dt = 2( 1 - N/1000)N - 100

now for equilibrium solution, dN/dt = 0

so

2( 1 - N/1000)N - 100 = 0

((1000 - N)/1000)N = 50

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approximately

N = 947 OR 53

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b)

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= 2N - N²/500 - 100

g'(N) = 2 - N/250

SO AT 947

g'(N) = g'(947) =  2 - 947/250 = -1.788 which is less than (<) 0

so N = 947 is stable equilibrium

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g'(N) = g"(53) = 2 - 53/250 = 1.788 which is greater than (>) 0

so N = 53  is unstable equilibrium

The capacity k=1000

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