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AfilCa [17]
3 years ago
13

Factor completely 2x5 + 10x4 - 22x3.

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:  2x³(x² + 5x - 11)

<u>Step-by-step explanation:</u>

2x⁵ + 10x⁴ - 22x³

Factor out the GCF (2x³)

2x³(x² + 5x - 11)

Since there are no values whose product is -11 and sum is +5, this cannot be factored further.

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NEED HELP ASAP
ivann1987 [24]

Answer:

I believe the answer is B, and the other answer is D.

4 0
2 years ago
Read 2 more answers
In the figure if angleACB = angleCDA, AC = 8 cm and AD= 3 cm, then BD is<br>​
tatiyna

Answer:

AC = 8 cm,

AD = 3 cm and ∠ACB = ∠CDA

From figure,

∠CDA = 90°

∴ ∠ACB = ∠CDA = 90°

In right angled ∆ADC,

AC2 = AD2 + CD2

⇒ (8)2 = (3)2 + (CD)2

CD2 = 64 – 9 = 55

⇒ CD = √55 cm

In ∆CDB and ADC.

∠BDC = ∠AD [each 90°]

∠DBC = ∠DCA [each equal to 90°-∠A]

∴ ∠CDB ∼ ∆ADC

Then,

6 0
2 years ago
Need fast help
kumpel [21]
I don't know what a radicals is and I can't really show my work cuz I just do it all in my head but I'll solve it for you.

A) (2)(x^2-5x-4) this one can't be simplified anymore unless you use the quadratic formula which I'm too lazy to do

B) (2x-1)(2x-5)
X=1/2 or 5/2
6 0
3 years ago
A group of 59 randomly selected students have a mean score of 29.5 with a standard
algol [13]

Answer:

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

\bar X = 29.5 represent the sample mean

\mu population mean  

s= 5.2 represent the sample standard deviation

n=59 represent the sample size  

Confidence interval

The confidence interval for the true mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=59-1=58

The Confidence interval is 0.90 or 90%, the significance is \alpha=0.1 and \alpha/2 =0.05, and the critical value is t_{\alpha/2}=1.671

Now we have everything in order to replace into formula (1):

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

8 0
2 years ago
110 decreased by 70%
Bess [88]
110x0.7= 77
110-77= 33
so 33 is your answer
7 0
2 years ago
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