Answer: C. (-3, 9)
Step-by-step explanation:
Given
2|x-3|=12
Divide both sides by 2
2|x-3|/2=12/2
|x-3|=6
Take of absolute value sign (REMEMBER need to take into consideration of two conditions)
x-3=±6
1)x-3=6
x=9
2)x-3=-6
x=-3
**NOTE**: need to check each solution whether or not they are suitable
Hope this helps!! :)
Please let me know if you have any questions
Problem 1
x = measure of angle N
2x = measure of angle M, twice as large as N
3(2x) = 6x = measure of angle O, three times as large as M
The three angles add to 180 which is true of any triangle.
M+N+O = 180
x+2x+6x = 180
9x = 180
x = 180/9
x = 20 is the measure of angle N
Use this x value to find that 2x = 2*20 = 40 and 6x = 6*20 = 120 to represent the measures of angles M and O in that order.
<h3>Answers:</h3>
- Angle M = 40 degrees
- Angle N = 20 degrees
- Angle O = 120 degrees
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Problem 2
n = number of sides
S = sum of the interior angles of a polygon with n sides
S = 180(n-2)
2700 = 180(n-2)
n-2 = 2700/180
n-2 = 15
n = 15+2
n = 17
<h3>Answer: 17 sides</h3>
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Problem 3
x = smaller acute angle
3x = larger acute angle, three times as large
For any right triangle, the two acute angles always add to 90.
x+3x = 90
4x = 90
x = 90/4
x = 22.5
This leads to 3x = 3*22.5 = 67.5
<h3>Answers:</h3>
- Smaller acute angle = 22.5 degrees
- Larger acute angle = 67.5 degrees
Answer:
<h3>425÷5 = 85</h3><h3>I hope it helps. ❣❣</h3>
Answer:
4
Step-by-step explanation:
