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Monica [59]
3 years ago
12

The coordinates of trapezoid ABCD are A(−4, 3), B(2, 3), C(4, −1) and D(−4, −1). A line segment runs through the trapezoid with

endpoints Y(−4, 1) and Z(3, 1). If trapezoid ABCD is dilated by a scale factor of 3 creating the new trapezoid of A′B′C′D′, what can you say about the length of line segment Y′Z′?

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0

We can say about the length of line segment Y'Z' will increase by the length of 3

madam [21]3 years ago
5 0
The distance from point Y to the y-axis is 4 units and the distance from point Z to the y-axis is 3 units, then the lelgth of the segment YZ is 4+3=7 units.
If <span>a scale factor is 3, then the length of Y'Z' will be 7·3=21 units.
</span>
P.S. In the added picture you can see trapezoid ABCD that was dilated by a scale factor 3 about the origin. This may help to understand that all linear values after dilation become multiplied by scale factor.
<span> </span>

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Write an equation for the nth term of the arithmetic sequence 23, 16, 9, 2, .... Then find a25.
Gelneren [198K]

Answer: i have no idea

Step-by-step explanation: i dont know sorry

3 0
2 years ago
How do I solve this? Please show steps clearly so i can understand, thank you
Lesechka [4]

Answer:

The value of x=8.

Step-by-step explanation:

Given:

\frac{x+3}{x}-\frac{x+1}{x+4}=\frac{5}{x}

We need to solve this equation.

Solution:

First combining equation having same denominators we get;

\frac{x+3}{x}-\frac{5}{x}=\frac{x+1}{x+4}

Now denominators are common so we will solve the numerators we get;

\frac{x+3-5}{x}=\frac{x+1}{x+4}\\\\\frac{x-2}{x}=\frac{x+1}{x+4}

Now by cross multiplication we get;

(x-2)(x+4)=x(x+1)

Now Applying distributive property we get;

x^2+4x-2x-8=x^2+x\\\\x^2+2x-8=x^2+x

Now Combining the like terms we get;

x^2+2x-x^2-x=8\\\\x=8

Hence on solving we get the value of x=8.

3 0
3 years ago
Help meee!!!!?!?!!?!?!?!?!?!?!?!?!?!!? 30 points
vivado [14]

Answer:

|-12|>|8|

Step-by-step explanation:

Solve absolute value.

|-12|=12

|8|=8

12 is greater than 8. Use greater than symbol.

12>8

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%284v%5E%7B-3%7D%20%29%5E3%2F3v%5E%7B-8%7D" id="TexFormula1" title="(4v^{-3} )^3/3v^{-8}" alt=
Svet_ta [14]

Answer:

=\frac{64}{3v}

Step-by-step explanation:

One is given the following equation:

\frac{(4v^-^3)^3}{3v^-^8}

Simplify the numerator, remember to raise every number inside the parenthesis to the exponent outside of the parenthesis. Bear in mind, an exponent raised to another exponent is equal to the exponent times the exponent it is raised to. Then simplify by multiplying the number by itself the number of times that the exponent indicates.

\frac{(4v^-^3)^3}{3v^-^8}

=\frac{4^3(v^-^3)^3}{3v^-^8}

=\frac{4^3v^-^9}{3v^-^8}

=\frac{64v^-^9}{3v^-^8}

Bring the variable (v) in the denominator (value under the fraction bar) to the numerator (value ontop of the fraction bar) by multiplying its exponent by (-1). This can be done simply because all operations in this equation are multiplication or division, remember, an exponent is another form of multiplication.

=\frac{64v^-^9}{3v^-^8}

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

Simplify, remember, multiplying two numbers with the same base that have an exponent is the same as adding the two exponents,

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

=\frac{(64v^-^9)(v^8)}{3}

=\frac{64v^-^9^+^8)}{3}

=\frac{64v^-^1}{3}

Now bring the variable to the denominator so that there are no negative exponents. Use a similar technique that was used to bring variables with exponents to the numerator.

=\frac{64v^-^1}{3}

=\frac{64}{3(v^(^-^1^)^(^-^1^))}

=\frac{64}{3v^1}

=\frac{64}{3v}

5 0
2 years ago
Write your answer in scientific notation (2.5•10^8)•(2•10^3)
ICE Princess25 [194]

Answer:

5\times10^{11}

Step-by-step explanation:

In order to get the answer to this question you will have to put the scientific notations into their number form then multiply, then change back into scientific notation form.

(2.5\times10^8)\times(2\times10^3)

Turn the notations into their number form:

2.5\times10^8

The exponent is positive so move the decimal point to the right:

2.5\times10^8=250000000

Do the same with the second notation:

2\times10^3

Since the exponent is positive move the decimal point to the right:

2\times10^3=2000

Now multiply:

250000000 \times 2000 = 500000000000

Now turn the number into scientific notation:

500000000000 = 5.0\times10^{11}

=5\times10^{11}

Hope this helps.

3 0
3 years ago
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