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cluponka [151]
3 years ago
11

Plot two points that are 3units from Point C and also share the same y-coordinate as Point C.

Mathematics
1 answer:
egoroff_w [7]3 years ago
6 0

The two points at a distance of 3 units from C with the same y coordinate are (-3, -5) and (-9, -5).

Step-by-step explanation:

Step 1:

First, we must plot the point C on the graph. Point C is on the third quadrant so the x value and the y value are negative.

The coordinate of C is (-6, -5).

We need to plot two points that are 3 units away from point C but have the same y coordinate i.e. y = -5.

Step 2:

So assume the two other points are A and B.

The y coordinates of A and B are -5. Only the x coordinate varies. So in order to get the coordinates of point A and B, we add and subtract 3 from the x coordinate of point C.

Point A = (-6+3, -5) = (-3,-5).

Point B = (-6-3, -5) = (-9, -5).

So two points at a distance of 3 units from C with the same y coordinate are (-3, -5) and (-9, -5).

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mina [271]

Answer:

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I think that's how you're supposed to answer it...

3 0
2 years ago
A rectangle has vertices at A(4,1), B(1,1), C(1,-6), and D(4,-6). What is the area of the rectangle?
slamgirl [31]

using the given coordinates, the rectangle is 7 by 3 units

area = 7*3 = 21 square units

8 0
3 years ago
Read 2 more answers
PLEASE PLEASE I NEED HELP
mrs_skeptik [129]

Answer:

12:42 pm

Step-by-step explanation:

that is my guess to be honest.

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6 0
3 years ago
In Happyville, the ideal family has four children, at least two of which are girls. If you randomly select a Happyville family t
sleet_krkn [62]

Answer:

0.3125 = 31.25% probability that it is not ideal.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it is a girl, or they are not. The probability of a child being a girl is independent of any other child. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.5 probability of a children being a girl:

This means that p = 0.5

If you randomly select a Happyville family that has four children, what is the probability that it is not ideal?

Not ideal is less than two girls, so this is P(X < 2).

Four children means that n = 4. So

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.5)^{0}.(0.5)^{4} = 0.0625

P(X = 1) = C_{4,1}.(0.5)^{1}.(0.5)^{3} = 0.25

P(X < 2) = P(X = 0) + P(X = 1) = 0.0625 + 0.25 = 0.3125

0.3125 = 31.25% probability that it is not ideal.

7 0
2 years ago
The ages of max and his father add up to 35 years. Max's father's age is the same as five more than the square of max's age
34kurt
M+f=35
f=5+m^2
sub 5+m^2 for f
m+5+m^2=35
m^2+m+5=35
minus 35 both sides
m^2+m-30=0
factor
what 2 numbers mulitply to get -30 and add to get 1
-5 and 6
(m-5)(m+6)=0
set to zto
m-5=0
m=5

m+6=0
m=-6
age can't be negative

max is 5
father is 30
5 0
3 years ago
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