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nataly862011 [7]
3 years ago
5

17. Your goal is to save at least $360.00 over the next 6 weeks. How much money must you save each week in order to meet that go

al? write and solve the inequality
A. 6+x>_360; x>_354
B. 60x>_360; >_10
C. x/6>_360; >_2160
D. 6x>_360; x>_60
Mathematics
1 answer:
OLga [1]3 years ago
4 0
<h2>Answer </h2>

D. 6x>_360; x>_60

<h2>Explanation</h2>

Let x be amount you will save each weeks

Since we know that you are saving over a period of 6 weeks, you will save 6x.

We also now that your goal is to save at least $360.00 over the period of 6 weeks, so saving more than $360.00 will be very desirable, but the goal is to save $360.00. We can rephrase this as: You need to save $360.00 or more; we can say the same using the inequality symbol \geq (greater on equal than)

Now we can combine our tow parts using the inequality symbol:

6x\geq 360

To simplify divide both sides by 6:

\frac{6}{6} x\geq \frac{360}{6}

x\geq 60

You need to save at least $60 per week, so the correct answer is D. 6x>_360; x>_60



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given that A=43 degrees , B=82 degrees and c=28, solve triangle ABC. Round to the nearest hundredth. A) C= 93 degrees , b= 33.8
n200080 [17]
A=43°
B=82°
c=28

1) A+B+C=180°
Replacing A=43° and B=82° in the equation above:
43°+82°+C=180°
125°+C=180°
Solving for C. Subtracting 125° both sides of the equation:
125°+C-125°=180°-125°
C=55° (option B or C)

2) Law of sines
a/sin A=b/sin B=c/sin C
Replacing A=43°, B=82°, C=55°, and c=28 in the equation above:
a/sin 43°=b/sin 82°=28/sin 55°

2.1) a/sin 43°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 43°:
sin 43°(a/sin 43°)=sin 43°(28/sin 55°)
a=28 sin 43° / sin 55°
Using the calculator: sin 43°=0.681998360, sin 55°=0.819152044
a=28(0.681998360)/0.819152044
a=23.31185549
Rounded to one decimal place
a=23.3

 2.2) b/sin 82°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 82°:
sin 82°(b/sin 82°)=sin 82°(28/sin 55°)
b=28 sin 82° / sin 55°
Using the calculator: sin 82°=0.990268069, sin 55°=0.819152044
b=28(0.990268069)/0.819152044
b=33.84903466
Rounded to one decimal place
b=33.8

Answer: Option B) C=55°, b=33.8, a=23.3
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Given that :

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P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

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Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

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