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KengaRu [80]
3 years ago
13

Z= 37 51 39 Triangles and Trigonometry

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

z =  { \tan( \frac{10}{8} ) }^{ - 1}  \\ z =(51.34019174591)

So the corect answer is (51)

You might be interested in
5. Identify the type and subtype of each of the fol-
r-ruslan [8.4K]

Answer:

a) Kylie has 8 marbles

b) 7 Cylinders

c) 17 carrots

d) 8 marbles belong to Shauntay

Step-by-step explanation:

5. Identify the type and subtype of each of the fol-

lowing problems.

a. Shawn has 15 marbles, which is 7 more marbles than Kyle has. How many marbles does Kyle have?

Shawn = 15 marbles

S = K + 7

15 = K + 7

K = 15 - 7

K = 8 marbles

Kylie has 8 marbles

b. Tiffany has 12 blocks, 5 of which are cubes and the rest cylinders. How many blocks are cylinders?

T = 12 blocks

Cubes = 5

Cylinders = the rest

12 blocks = Cubes + Cylinders

Cylinders = 12 - Cubes

Cylinders = 12 - 5

Cylinder = 7

c. Peter had some carrots. After he ate 3 of them, he had 14 carrots left. How many carrots did Peter have before?

Number of carrots Peter has before

= Number of carrots he ate + Number of carrots he has now

= 14 + 3

= 17 carrots

d. In a bag of 17 marbles, 9 marbles belong to Kelly and the rest belong to Shauntay. How many marbles belong to Shauntay?

Total number of Marbles = 17

Kelly = 9 marbles

Shauntay = ?

Total = Kelly + Shauntay

Shauntay = Total - Kelly's marbles

= ( 17 - 9) marbles

= 8 marbles

8 marbles belong to Shauntay

6 0
3 years ago
Read 2 more answers
If point (4,5) is on the graph of a function, which equation must be true?
DochEvi [55]
The answer is f(4)=5
4 0
3 years ago
what is always true about a line that Slants downward from left to right select all that apply help plz​
____ [38]

Answer:

A line that slants down from left to right has a negative slope. Horizontal and vertical lines also have a slope.

Step-by-step explanation:

4 0
3 years ago
Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
1 year ago
Suppose you want to eat lunch at a popular restaurant. The restaurant does not take reservations, so there is usually a waiting
grin007 [14]

Answer:

a) z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{15-19}{4} =-1

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-1)=1-P(z

And replacing we got:

P(X >20| X>15)= \frac{0.401}{0.841}= 0.477

b) z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{18-19}{4} =-0.25

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-0.25)=1-P(z

And replacing we got:

P(X >20| X>18)= \frac{0.401}{0.599}= 0.669

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the length of time waiting to be seated of a population, and for this case we know the distribution for X is given by:

X \sim N(19,4.0)  

Where \mu=19 and \sigma=4.0

Part a

For this cae we want to find this probability:

P(X >20| X>15)

And if we use the conditional probability formula we got:

P(X >20| X>15)= \frac{P(X >20 \cap X>15)}{P(X>15)}=\frac{P(X>20)}{P(X>15)}

We can solve the problem using the z score formula given by:

z = \frac{x-\mu}{\sigma}

z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{15-19}{4} =-1

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-1)=1-P(z

And replacing we got:

P(X >20| X>15)= \frac{0.401}{0.841}= 0.477

Part b

P(X >20| X>18)= \frac{P(X >20 \cap X>18)}{P(X>18)}=\frac{P(X>20)}{P(X>18)}

We can solve the problem using the z score formula given by:

z = \frac{x-\mu}{\sigma}

z_1 =\frac{20-19}{4} =0.25

z_2 =\frac{18-19}{4} =-0.25

And we can use the complement rule and we got:

P(z>0.25)=1-P(z

P(z>-0.25)=1-P(z

And replacing we got:

P(X >20| X>18)= \frac{0.401}{0.599}= 0.669

5 0
4 years ago
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