Question

A particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams. The heaviest 2% of fruits weigh more than how many grams? Give your answer to the nearest gram.

Answer 1

Answer:

We get that the heaviest of fruits weigh 766.84 grams.

Step-by-step explanation:

We know that a particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams.

We have:

$\mu=738\\\\\sigma=14$

We calculate x:

$P(X$

We use the standard normal table and we get: Z=2.06.

So, we get

$2.06=\frac{x-738}{14}\\\\x-738=28.84\\\\x=766.84$

We get that the heaviest of fruits weigh 766.84 grams.