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VMariaS [17]
4 years ago
11

A particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams. The heavie

st 2% of fruits weigh more than how many grams? Give your answer to the nearest gram.
Mathematics
1 answer:
posledela4 years ago
5 0

Answer:

We get that the heaviest of fruits weigh 766.84 grams.

Step-by-step explanation:

We know that a particular fruit's weights are normally distributed, with a mean of 738 grams and a standard deviation of 14 grams.

We have:

\mu=738\\\\\sigma=14

We calculate x:

P(X

We use the standard normal table and we get: Z=2.06.

So, we get

2.06=\frac{x-738}{14}\\\\x-738=28.84\\\\x=766.84

We get that the heaviest of fruits weigh 766.84 grams.

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The surface area of a prism can be found by using this formula: 
<span>SA=bh+(s1+s2+s3)H</span>
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14x 0 = 0<br> What property is this statement please lmk ASAP!!
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Answer:

The multiplication property of zero

Step-by-step explanation:

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In ΔABC (m∠C = 90°), the points D and E are the points where the angle bisectors of ∠A and ∠B intersect respectively sides BC an
alexira [117]

Proof: \triangle CEH and \triangle CDG are isosceles triangles.

Explanation: Given in \triangle ABC D and E are angle bisector of   \angle Aand \angle B respectively.

Where G and H are points in AB such that DG\perp AB and EH\perp AB.

Let us take two triangles \triangle BCE and \triangle BEH

\angle BCE=\angle BHE (Right angles)

BE=BE, (common segment)

\angle HBE=\angle CBE ( Because BE is angle bisector)

Thus, \triangle BCE\cong\triangle BEH(ASA)

Therefore, EH= CE (CPCT)

So, in \triangle CEH, EH=CE ⇒\triangle CEH is an isosceles triangle.

Now, in \triangle ACD and \triangle ADG,

\angle ACD=\angle AGD (Right angles)

AD=AD (common segment)

\angle CAD=\angle DAG ( Because AD is angle bisector)

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4 0
4 years ago
What is the slope of the line ? <br><br><br><br>a) -3<br>b) -1/3<br>c) 1/3<br>d) 3
dezoksy [38]
The answer is A) -3, Hope this helps
8 0
3 years ago
Read 2 more answers
Can someone please help me with this question and explain how you got the answer?
Marina CMI [18]
Answer: The height is roughly 20 mm

------------------------------------

Explanation:

Let's find the area of the circular base
This circle has a radius of 12, so r = 12
Plug this into the area of a circle formula to get...
A = pi*r^2
A = pi*12^2
A = pi*144
A = 144*pi
A = 144*3.14  <<-- replace pi with 3.14
A = 452.16
The area of the circle is roughly 452.16 square mm

There are two of these faces, so 2*A = 2*452.16 = 904.32 represents the total base area

The lateral surface area is unknown. Let's call it L for now. If we add the total base area (904.32) to the lateral surface area (L), we would get the complete surface area which is given to be 2411.52

So,
904.32+L = 2411.52
904.32+L-904.32 = 2411.52-904.32
L = 1507.2

The lateral surface area is roughly 1507.2 square mm

The formula for the lateral surface area of a cylinder is
L = 2*pi*r*h
We found L = 1507.2 and we know that r = 12, so let's use this to find h

L = 2*pi*r*h
1507.2 = 2*3.14*12*h
1507.2 = 75.36*h
1507.2/75.36 = 75.36*h/75.36
20 = h
h = 20

The height is roughly 20 mm

6 0
3 years ago
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