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adelina 88 [10]
2 years ago
9

How much of a radioactive kind of ruthenium will be left after 8 hours if you start with 3,888

Mathematics
2 answers:
ziro4ka [17]2 years ago
7 0

Answer:

Step-by-step explanation:

As an example, iodine-131 is a radioisotope with a half-life of 8 days. It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131.

50 grams to 25 grams is one half-life. 25 grams to 12.5 grams is another half-life. So, for 50 grams to decay to 12.5 grams, two half-lives, which would take 36 days total, would need to pass. This means each half-life for element X is 18 days.

MA_775_DIABLO [31]2 years ago
5 0

Answer:

After 8 hours or 2 half-lives, you will have 972 grams of ruthenium left.

Step-by-step explanation:

hope this helps. . . <3

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Davis Electronics manufactures a certain type of radio that requires 18 working resistors per radio. If one out of 22 resistors
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Since One Radio in Davis Electronics requires 18 working resistors, then 2,145 radios will require 18\times2145=38610 resistors.

Now we know that one out of 22 resistors is defective. This means that the number of non defective or perfect resistors in a set of 22 resistors is 21.

So, obviously, if we pick a set of 40,370 resistors then the set of working resistors we will get is 40370\times \frac{21}{22} =38535.

As can be clearly seen from the above calculations the required amount of working resistors is 38610 and the amount of working calculators available to us is 38535.

Thus, since the required amount of working resistors is greater than the amount of working resistors available, 40,370 resistors are not enough to assemble 2,145 radios.

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

By putting the given values of E and F we get,

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Here we will take the coefficient of same variable together

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