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4 years ago

THIS IS A SCIENCE QUESTION SRY

2 answers:

6 0

A is more likely. Heating something to fast and for too long can cause stress on the glass causing it to crack. Water wouldn’t have effected it

yaroslaw [1]4 years ago

3 0

Answer:

A. he held the tube iver the flame too long

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The first and second steps to solve the equation 3x/5+5=20 are

PtichkaEL [24]

Answer:

$66\frac{2}{3}$

Step-by-step explanation:

$\frac{3x}{5+5}=20\\\mathrm{Multiply\:both\:sides\:by\:}10\\\frac{10\cdot \:3x}{5+5}=20\cdot \:10\\Simplify\\3x=200\\\mathrm{Divide\:both\:sides\:by\:}3\\\frac{3x}{3}=\frac{200}{3}\\Simplify\\x=\frac{200}{3}$

$66\frac{2}{3}$

3 0

3 years ago

Read 2 more answers

Is the expression of y=1/7x and example of direct variation? If, yes then what is the constant of a variation

weqwewe [10]

Answer:

direct variation

constant = 1/7

Step-by-step explanation:

The equation for direct variation is

y = kx

y = 1/7 x is in this form with the constant of variation being 1/7

3 0

3 years ago

Read 2 more answers

Determine the center and radius of the following circle equation:

katen-ka-za [31]

Answer:

Center(10x,4y) radius 28

Step-by-step explanation:

if I am understanding correctly

8 0

3 years ago

ahrayia [7]

C. F(x)=4x2-2x+16 .....:...

6 0

4 years ago

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Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c

nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = \frac{81}{130} = 0.6231$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when $M = 0.04$