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igomit [66]
3 years ago
12

The three-dimensional figure below is a solid rectangular prism with a hole in the shape of another rectangular prism going thro

ugh the center of it. Find the volume of the solid in cubic millimeters.
A.60
B.300
C.540
D.780

Mathematics
1 answer:
vekshin13 years ago
5 0

So you need to find the volume for the rectangular prism (1) and the rectangular prism in the center of it (2)

The formula for a rectangular prism is:    

V = lwh         [Volume = length x width x height]      

1.

l = 15

w = 6

h = 6

V = lwh           Plug in the numbers

V = (15)(6)(6) = 540

2.

l = 15

w = 4

h = 4

V = lwh

V = (15)(4)(4) = 240

Next you subtract the volumes by each other because the rectangular prism in the center(2) is the hole/empty part of the rectangular prism(1)

V = V(1) - V(2)

V = 540 - 240

V = 300

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hope it helps
8 0
3 years ago
Read 2 more answers
Find two consecutive numbers whose sum is 155
Viefleur [7K]
83-73 will make up to 155
6 0
4 years ago
What is the distance between pints (-2 -5) and (3 -6)
sukhopar [10]

Answer:

\displaystyle d = \sqrt{26}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-2, -5)

Point (3, -6)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance<em> d</em>

  1. Substitute in points [DF]:                     \displaystyle d = \sqrt{(3--2)^2+(-6--5)^2}
  2. (Parenthesis) Simplify:                         \displaystyle d = \sqrt{(3+2)^2+(-6+5)^2}
  3. (Parenthesis) Add:                               \displaystyle d = \sqrt{(5)^2+(-1)^2}
  4. [√Radical] Exponents:                         \displaystyle d = \sqrt{25+1}
  5. [√Radical] Add:                                    \displaystyle d = \sqrt{26}
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3 years ago
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480 is probably correct
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Henry correctly factored 4x^(2)+5x-6 as (4x-3)(x+2). He then claimed that the zeros of that quadratic function are located at x=
svlad2 [7]

Answer:

I believe Henrey is wrong

Step-by-step explanation:

because the roots of the quadratic function are

<em>"</em><em>(</em><em>x</em><em>=</em><em> </em><em>3</em><em>/</em><em>4</em><em>,</em><em> </em><em>-</em><em>2</em><em>)</em><em>.</em><em>"</em>

4 0
2 years ago
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