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olasank [31]
2 years ago
6

Question 1 of 5 The Ridgeport school district collected data about class size in the district. The table shows the class sizes f

or five randomly selected kindergarten and seventh-grade classes. Number of students in randomly selected class Mean Mean absolute deviation Kindergarten 18, 20, 21, 19, 22 20 1.2 27, 32, 33, 33, 35 32 2 Seventh grade Based on these data, which statement is true?
sorry I couldn't fit the answer in it ​

Mathematics
2 answers:
exis [7]2 years ago
6 0

Answer:

C is the correct answer

Step-by-step explanation:

amid [387]2 years ago
6 0

Answer:

a. the average size of a seventh-grade class is larger and varies more than that of a kindergarten class.  

Step-by-step explanation:

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Choose the option with the proper number of sig figs
marishachu [46]
\text{ 2 }\times10^8

Explanation:\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}

let's break down the expression to get the final result:

\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\  \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\  \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\  \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}

6 0
1 year ago
Let f(x) = 5x^3 -2x and g(x) = 3x^3. Perform the indicated operation and state the domain.
valentina_108 [34]

Answer:

54x^6 - 5

Step-by-step explanation:

6 0
2 years ago
Solve please I’m stuck
nata0808 [166]

= -36 4/9 + 10 2/9 - 18 2/9

= -26 2/9 - 18 2/9

= -44 4/9

Answer is A.  -44 4/9

7 0
3 years ago
lotA has 4,000 spaces. Today Lot A has 2,500 cars in Lot A. Lot B has 2,000 spaces. If both lots have the same ratio of cars to
ch4aika [34]
Lot B has half the spaces of lot A, so will have half the cars: 1,250.
8 0
3 years ago
What are the answers
Nastasia [14]
All ur answers are correct except #4 and #10. so #4 is 789,600 and #10 is 45,110,000
6 0
3 years ago
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