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inessss [21]
3 years ago
10

Need help solving for X

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0
In the triangle shown above,
tan 75 = P / B
3.73 = 300 / x    [ tan 75 = 3.73 ]
x = 300 / 3.73
x = 80.42
After round-off to the nearest tenth, it would be 80.4

So, your final answer is x = 80.4

Hope this helps!
MAXImum [283]3 years ago
4 0
I believe that x=20 from the math i did hopefully its helpful.
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Find the vertex of the parabola.<br> x² + y - 6x + 10 = 0
Drupady [299]
Find the Vertex Form

y = -(x-3)^2-1
3 0
3 years ago
Workout 2/5 of 16 miles
yaroslaw [1]

Answer:

6.4

Step-by-step explanation:

16 ÷ 2/5 = 6.4!

that's it

3 0
3 years ago
please help in the picture below (top left is A) (bottom left is B) top right is C ) and bottom right is D) (will report for non
Phoenix [80]
For this you count rise over run aka how many up divided by how many over starting from 0. here it’s 7 up and 3.5 side, 7 divided by 3.5 is 2 and the line is going down so it’s negative 2 (D)
3 0
3 years ago
Read 2 more answers
A train leaves thorn junction at 1:25 p.m. and arrives in niles at 3:05 p.m. the train makes two stops along the route for a tot
KonstantinChe [14]

The time taken by the first and the second train is 1 hour 40 minutes and 1 hour 25 minutes. Then the time when the second train at Niles junction is 5:55 p.m.

<h3>What is speed?</h3>

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

\rm Speed = \dfrac{Distance}{Time}

A train leaves Thorn junction at 1:25 p.m. and arrives in Niles at 3:05 p.m. the train makes two stops along the route for a total of 15 minutes.

A second train leaves Thorn junction at 4:30 p.m. and heads to Niles.

This train does not make any stops.

Let the speed of both trains be equal.

Then the time taken by the first train will be

t₁ = 3:05 p.m. - 1:25 p.m.

t₁ = 1 hour 40 minutes

Then the time taken by the second train will be

t₂ = 1:40 - 00:15

t₂ = 1:25 = 1 hour 25 minutes

The time when the second train is at Niles junction will be

→ 4:30 p.m. + 1:25

→ 5:55 p.m.

More about the speed link is given below.

brainly.com/question/7359669

#SPJ1

3 0
2 years ago
H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
zubka84 [21]
H(x)=(x^2)+1\ \ \ \ and\ \ \ \  K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.
4 0
3 years ago
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