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3 years ago

Marking brainliest if correct Solve the PROPORTION 3/4 = 1/2y y=

Mathematics

1 answer:

Vladimir79 [104]3 years ago

4 0

Answer:

y=1 1/2 (fraction)

y=1.5 (decimal)

Step-by-step explanation:

We want to get y alone, so we need to get rid of the 1/2 in front of it. To do that we can multiply each side by 2 since 1/2 + 1/2 = 1.

3/4= 1/2y

multiply each side by 2

To multiply 3/4 by 2 you need to multiply the numerators and then multiply the denominators

2•3=6 & 4 • 1 =4

6/4

simplify

y=1 1/2

(If you need it in decimal form it would be y=1.5)

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

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Id iotn like branly plus it keep asking for money and it s super annoying

PIT_PIT [208]

Answer:

YESSSS ikr like every minute it say UpGrAdE uR bRaInLy and its just ike I ALREADY DIDDDDDD it is VERYYY anouing

Step-by-step explanation:

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3 years ago

The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am

posledela

Step-by-step walkthrough:

Well a standard half-life equation looks like this.

$N = N_0 * (\frac{1}{2})^{t/p$

$N_0$ is the starting amount of parent element.

$N$ is the end amount of parent element

$t$ is the time elapsed

$p$ is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days$

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2} = 37g$

Now we just gotta do some algebra. Use the original function but this time, replace $N(t)$ with 10g and solve algebraically.

$10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}$

Take the log of both sides.

$log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})$

Use the exponent rule for log laws that, $log(b^x) = x*log(b)$

$log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})$

$\frac{log(\frac{5}{37})}{log(\frac{1}{2})} = \frac{t}{2.8days}$

$2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})} = t$

slap that in your calculator and you get

$t = 8.1 days$

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2 years ago

Find the height of a prism whose volume is 108 cm3<br> and the area of the base is 15 cm2.

cluponka [151]

Answer:17

Step-by-step Experlation: The volume is 108 cm. 3,2,15.a square prism with a base edge of 9.5 inches and a height of 17 ... amount for a landowner

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2 years ago

Jayden has been reading a 275275275-page book for English class. On average, he has read about 101010 pages in 151515 minutes (\

maxonik [38]

First let's define variables:
r: reading
s: skimming
We write the system of equations that adapts to the problem:
r + s = 275
(15/10) r + (10/15) s = 355
We solve the system of equations:
r = 206
s = 69
Note: see attached image for system solution.
Answer:
Jayden had to skim 69 pages through

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3 years ago

PLEASE HELP!

emmainna [20.7K]

Use the given recursion and starting value of $x_0 = 2.4$ to find $x_1$ :

$x_1 = \dfrac{x_0 + \frac6{x_0}}2 = \dfrac{2.4 + \frac{6}{2.4}}2 = 2.45$

Do the same for $x_2$ and $x_3$ :

$x_2 = \dfrac{x_1 + \frac6{x_1}}2 = \dfrac{2.45 + \frac6{2.45}}2 \approx 2.44949$

$x_3 = \dfrac{x_2+\frac6{x_2}}2 \approx \dfrac{2.44949 + \frac6{2.44949}}2 \approx \boxed{2.44949}$

(That's not a mistake. This just tells you that the 2nd and 3rd iterates are very close together and have at least the same first 5 digits after the decimal.)

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2 years ago