Each row has two more boxes than the row above. The first row has one box
The boxes in a row form an arithmetic sequence with the first term, a₁ = 1 and the common difference, d=2.
The n-th term is

The sum of n terms is

Answer:
The table will have the following:
Row Number: 1 2 3 4 5 6
Boxes in the row: 1 3 5 7 9 11
Total boxes in the display: 1 4 9 16 25 36
1 liter because 200 millimeters is 0.2 liter and 1.2 minus 0.2 equals 1 liter.
The mode is 4 because it is the number that shows up the most.
Answer: Probability P = 1/1716
Step-by-step explanation:
Definition
For permutation ( order is important)
nPr = n!/(n-r)!
Given;
Total number of members in the committee = 13
Total number of members to be selected = 3
Since order is important in this case.
The total number (Tt) of possible ways of selecting three executives from the committee members is given as
Tt = 13P3 (since order is important)
Tt = 13!/(13-3)!
Tt = 13!/10!
Tt = 1716
The probability P of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions is equal to
P = number of favourable outcomes/ number of possible outcomes
Number of favourable outcomes = 1 (i.e 1×1×1 = 1) one option for each post.
Number of possible outcomes = Tt = 1716
P = 1/1716