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3 years ago

Liam bought 11/8 cups of carrots. If Liam eats 2/8 cup in a serving, how many servings did Liam buy

Mathematics

1 answer:

Svetach [21]3 years ago

4 0

Answer:

13/8

Step-by-step explanation:

11/8 plus 2/8 that's he ate equals 13/8

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The president of Doerman Distributors, Inc., believes that 30% of the firm's orders come from first-time customers. A random sam

Tanzania [10]

Answer:

Step-by-step explanation:

p = .3

n = 150

p(bar ) = 1 - p = .7

$\sigma_p=\sqrt\frac{p(1-p) }{n} }$

$\sigma_p=\sqrt\frac{.3(1-.3) }{150} }$

=.037

b )

P ( .2 <p<.4 ) = P [ (.2 - .3) / .037 < z < ( .4 - .3 ) / .037 ]

= P [ (-2.7 < z < +2.7 ]

= .9965-.0035

= .993

c )

P ( .25 <p<.35 ) = P [ (.25 - .3) / .037 < z < ( .35 - .3 ) / .037 ]

= P [ (-1.35 < z < +1.35 ]

= .9115 - .0885

= .823

4 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap

11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=20$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20$

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

$h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)$