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alina1380 [7]
3 years ago
13

The diagram is a straightedge and compass construction. A is the center of one circle, and B is the center of the other.

Mathematics
1 answer:
Triss [41]3 years ago
3 0
You could use Pythagoras Theorem to solve this.

All the points are equidistant from the centre of line AB, therefore it is just the same triangle but rotated. I hope this help but I can show you on paper if you don’t understand that answer :)
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Please tell the answer and show the work.
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First step, i would try to figure out the slope. think of it as a typical y=mx+b linear equation as you check out the graph.

it's just rise over run (rise up this many, run over that many), and your options are (-2/3) or (-3/2)

start at the y-intercept, which is just above the middle of the graph. if you go down 2 and try to go over 3, you hit the line before you can count 3 units. that means this slope is incorrect.

go back to the y-intercept. down 3, over 2--there you go. your slope here is (-3/2), which immediately gets rid of half your answer choices for having the wrong slope

the next thing you have to do is decide <em>where</em> this graph should be shaded. the shaded region shows the domain; the white region shows what's outside of your domain. this inequality is shaded "below" which means that the y values are LESS than "(-3/2)x +1"

that eliminates another one of your answer choices; choice 3 is correct. the inequality is y < (-3/2)x + 1

if the graphs of inequalities are shaded below and the line is dotted, it's less than. if the graphs of inequalities are shaded above and the line is dotted, it's greater than. general rules for ya
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