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miskamm [114]
3 years ago
9

Will Give Brainliest ! Please Helppp!!!

Mathematics
1 answer:
Kryger [21]3 years ago
3 0

Answer:

The Seccond One, B

Step-by-step explanation:

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Whats -3 divided by 7
shutvik [7]

Answer:

-3 over 7 or -0.429

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Find the area of each figure. round to the hundredths place when necessary
notsponge [240]

Answer:

115.48m^{2}

Step-by-step explanation:

This shape can be split into two distinct shapes

Two halves of a semi circle, and a rectangle in between

Circle:

Putting both halves of the semi circle together will give you a full circle. The diameter of the circle is given (7m).

The area of a circle is A = π r^{2}

The radius, r, is half of the diameter, so 7 / 2 = 3.5m

A = π r^{2}

A = π * 3.5^{2}

A = 38.38m^{2}

Rectangle:

The area of a rectangle is A = h b

The height, h, is known at 7m

The base, b, can be found by removing the length from the dot to the end of the semi circles. This length is the radius of the semi circles, 3.5m

Removing the radius from the total length given

18 - 3.5 - 3.5 = 11m

The base is 11m

A = h b

A = 7 * 11 = 77m^{2}

Total Area = Circle area + Rectangle area

Total Area = 38.38 + 77 = 115.48m^{2}

6 0
3 years ago
Find the missing amount)
Afina-wow [57]
136/160=x/100

Cross multiply and divide:

136*100=13600
13600/160=85

Answer: 85%
7 0
3 years ago
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PLZZ HELP!!!!!!!!!!!!!!!!!! ASKED QUESTION ALREADY BUT ANSWER WAS NOT IN SELECTION
timofeeve [1]

Step-by-step explanation:

so the correct answer is 3³

6 0
3 years ago
Help im diening please
Alina [70]

Answer:

y = x + 3

Step-by-step explanation:

To know which of the equations represent the relationship between x and y, you need to substitute the x and y values into the equation. If when the equation is solved, the left-hand and right-hand side of the equation equal each other and hence the equation is true, then the equation must be correct in expressing the relationship between the x and y values. If not, then it is not correct.

As this question is only dealing with linear equations, we know that the gradient of the line is constant and hence the rate of change in x and y values is constant. Therefore, we can choose to substitute any of the given combinations of x and y values into the equation to obtain the correct equation. As it is easier to use smaller numbers for smaller calculations, we'll use the first combination of x = 1 and y = 4 .

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>1</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>3x</em><em> </em><em>+</em><em> </em><em>1</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em><em> </em><em>and</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>5</em>

( 4 ) = 3 ( 1 ) + 1

4 = 4

However, as this equation has a constant not equal to 1 in front of the x variable and hence a different gradient to the other equations, we will substitute the second combination of x and y values.

( 5 ) = 3 ( 2 ) + 1

5 = 6

Therefore, equation is false / incorrect.

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>2</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>1</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em>

( 4 ) = ( 1 ) + 1

4 = 2

Therefore, equation is false / incorrect.

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>3</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em>

( 4 ) = ( 1 ) + 3

4 = 4

Therefore, equation is true / correct.

<em>Equation</em><em> </em><em>No</em><em>.</em><em> </em><em>4</em><em> </em><em>:</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>where</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>4</em>

( 4 ) = ( 1 ) - 3

4 = - 2

Therefore, equation is false / incorrect.

8 0
3 years ago
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