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3 years ago

Will Give Brainliest ! Please Helppp!!!

Mathematics

1 answer:

Kryger [21]3 years ago

3 0

Answer:

The Seccond One, B

Step-by-step explanation:

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Whats bigger 7/12 or 3/4

inessss [21]

3/4 will be the bigger value of the two

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=8%5E%7B2%7D%3Dx%5C%5Cx%2B12%3Dy%5C%5Cy-3%3Dn%5C%5Cn%3D%3F" id="TexFormula1" title="8^{2}=x\\x+

AlexFokin [52]

Answer:

n = 73

Step-by-step explanation:

8² = x ==> x = 64

x + 12 = y ==> y = 64 + 12 = 76

y – 3 = n ==> n = 76 – 3 = 73

Follow my account ^^

8 0

3 years ago

Read 2 more answers

If someone can answer all these ill give 100 points

Helga [31]

Answer:

1. x = -6

2. x = 2

3. x = 6

4. x = 3

5. x = -5

6. x = -1

7. x = 0

8. x = 9

9. x = -4

10. x = 7

Step-by-step explanation:

$-10x = -8x + 12$

$-10x+8x=-8x+12+8x$
$-2x=12$

$-2x/-2=12/-2$
$x=-6$

$9-5x+x=1-x+x$
$-4x+9=1$

$-4x+9-9=1-9$
$-4x=-8$

$-4x/-4=-8/-4$
$x=2$

$-2x+16-x=x-2-x$
$-3x+16=-2$

$-3x+16-16=-2-16$
$-3x=-18$

$-3x/3=-18/-3$
$x = 6$

$(-4)(6x)+(-4)(-2)= -8x-40$
$-24x+8=-8x-40$

$-24x+8+8x=-8x-40$
$-16x+8=-40$

$-16x+8-8=-40-8$
$-16x=-48$
$-16x/-16=-48/-16$
$x=3$

$37 - 8x = (-7)(x)+(-7)(-6)$
$-8x+37=-7x+42$
$-8x + 37 + 7x = -7x + 42 + 7x$
$-x+37=42$
$-x+37-37=42-37$
$-x=5$
$-x/-1=5/-1$
$x=-5$

$6x+(-2)(2)+(-2)(8x) = 10 + 4x$
$6x-4-16x = 10 + 4x$
$-10x - 4 = 4x + 10$
$-10x - 4 -4x=4x+10-4x$
$-14x-4=10$
$-14x-4+4=10+4$
$-14x=14$
$-14x/-14=14/-14$
$x=-1$

$(-2)(x) + (-2)(1) = (2)(x) + (2)(-1)$
$-2x-2=2x-2$
$-2x-2-2x = 2x - 2 - 2x$
$-4x - 2 = -2$
$-4x-2+2=-2+2$
$-4x=0$
$-4x/-4=0/-4$
$x=0$

$(-3)(x)+(-3)(3)=(-6)(x)+(-6)(-3)$
$-3x-9=-6x+18$
$-3x-9+6x=-6x+18+6x$
$3x-9=18$
$3x-9+9=18+9$
$3x=27$
$3x/3 = 27/3$
$x=9$

$6x-36=(-4)(-2x)+(-4)(7)$
$6x-36= 8x -28$
$6x-36-8x = 8x - 28 - 8x$
$-2x-36=-28$
$-2x-36+36=-28+36$
$-2x = 8$
$-2x/-2=8/-2$
$x=-4$

10.

$(2)(x)+(2)(1) = -2x + 30$
$2x+2=-2x+30$
$2x+2+2x=-2x+30+2x$
$4x+2=30$
$4x+2-2=30-2$
$4x=28$
$4x/4=28/4$
$x=7$

4 0

2 years ago

Simplify. (5x^3y^2+x^2-6x^2y^3) - (3x^2y^3-4y^3+7x^2)

Zanzabum

Answer:

Step-by-step explanation:

The initial expression is:

$(5x^{3}y^{2}+x^{2}-6x^{2}y^{3})-(3x^{2}y^{3}-4y^{3}+7x^{2})$

Using BEMDAS (Brackets - Exponents - Multiplication - Division - Addition -Subtraction), we first start with brackets:

$5x^{3}y^{2}+x^{2}-6x^{2}y^{3}-3x^{2}y^{3}+4y^{3}-7x^{2}$

Remember that if there is a negative sign, it will change the signs of the terms within the brackets.

Then, collecting like terms:

$5x^{3}y^{2}-9x^{2}y^{3}+4y^{3}-6x^{2}$

5 0

3 years ago

Solve tan x + 1 = 0 for x.

MAXImum [283]

Tan x + 1 = 0
tan x = -1
x = -π/4 + nπ ( n ∈ Z )

5 0

3 years ago

Read 2 more answers