Answer:
You invested $13,000 in two accounts... You invested $13,000 in two accounts paying 5% and 7% annual interest, respectively. If the total interest earned for the year was $850, how much was invested at each rate?
Answer:
9x-7y+28=0
Step-by-step explanation:
using formula
y-y1=m(x-x1)
y-4=9/7(x-0)
7y-28=9x
9x-7y+28=0
The preferred gig is the first one since its today's worth is greater than the today's value of the second gig
What is the today's worth of $5000 each year?
The worth of the second gig, which pays $5000 every year for the next 6 years in today's dollar is the present value of all the six annual cash flows discounted using the present value formula of an ordinary annuity as shown below:
PV=PMT*(1-(1+r)^-N/r
PV=present value of annual payments for 6 years=unknown
PMT=annual payment=$5000
r=required return=discount rate=8%
N=number of annual cash flows=6
PV=$5000*(1-(1+8%)^-6/8%
PV=$5000*(1-(1.08)^-6/0.08
PV=$5000*(1-0.630169626883105)/0.08
PV=$5000*0.369830373116895
/0.08
PV=$23,114.40
The fact that the present value of the second option which pays $5000 annually is lesser than the amount receivable immediately, which is $25,000, hence, the first gig is preferred
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Answer:
45.7
Step-by-step explanation:
Hello there!
We can calculate the missing angle using trigonometry
here are the trigonometric ratios
sin = opposite over hypotenuse
cos = adjacent over hypotenuse
tan = opposite over adjacent
We are given x's opposite side length (8) and x's adjacent side length (7.8)
we are given the information to use the trigonometric ratio tangent
so now we create an equation (remember tan - opposite over tangent)

now we solve for x

we're left with

finally we want to get rid of the tan
To do so we take the inverse of tan (arctan^-1) and apply it to each side

so x = 45.7252243
finally we round to the nearest tenth and get that the answer is
45.7
Answer:
Exact form: x=19/9
decimal form: x=2.1r
Mixed number form: x=2 1/9
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.