Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
Answer:
- tn = 2097152 pennies
- tn = 20971.52 dollars.
Step-by-step explanation:
A surprisingly large amount of money.
The question is "Does the amount of money just double or do the previous amounts add to the present amount?"
I think it just doubles. Not only that, but she can't spend any of it until night 22 is reached.
- tn = a*2^(n - 1)
- a = 1 She starts with 1 penny.
- n = 22
- tn = 1*2^(22 - 1)
- tn = 1*2^21
- tn = 2097152 pennies
- tn = 20971.52 dollars.
The price of this more expensive book was $90.00 ($150 - $60) based on the date acquired from the question above. This problem can be solved using a simple algebra equation which consisted of one variable. The equation is stated as $150 = x + 1.5x (x = $150/2.5 = $60) where x is the price of the cheaper book and 1.5x is the price of the more expensive books because it has 50% higher price than the cheaper book<span>.</span>
