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Kipish [7]
3 years ago
10

Find missing length

Mathematics
1 answer:
svetlana [45]3 years ago
6 0
By the Pythagorean theorem
.. 15^2 = 10^2 +a^2
.. 225 = 100 +a^2
.. 125 = a^2
.. √125 = a
.. 5√5 = a ≈ 11.18
The missing side length is 5√5 cm.
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Which diagram BEST represents the relationship among integers, rational numbers, and whole numbers?
Ronch [10]

Answer:

The correct option is;

A)

Step-by-step explanation:

By the representation of numbers in a figurative for, we have;

1) Th rational numbers that can be expressed in the form a/b, where a and b are real numbers

2) The integers are the direct subset of the set of rational numbers and are displayed in he next larger ellipse in the figure

3) The whole numbers are the direct subset of the set of integers.

8 0
3 years ago
A quarter is worth of a dollar. Haley needs to exchange dollar bills to get quarters to do her laundry in coin washers and dryer
Ira Lisetskai [31]

Answer:

52 quarters

Step-by-step explanation:

-We know that a quarter dollar is equivalent to $0.25

\$1=4 \ Quarters

-Given that Haley has $13, we multiply this amount by 4 since $1 has 4 quarters to obtain the number of quarters:

Q=13\times 4\\\\=52

Hence, Hayley will get 52 quarters.

8 0
2 years ago
In the lake there are 3 times as many largemouth bass as there are smallmouth bass. If Johnny randomly catches a bass at the lak
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6 0
2 years ago
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Does anyone know the answer
arsen [322]

Answer:

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Step-by-step explanation:

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2 years ago
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Set up a double integral for calculating the flux of the vector field ????⃗ (????⃗ )=????⃗ , where ????⃗ =⟨x,y,z⟩, through the p
Tema [17]

Answer:

-937.5π

Step-by-step explanation:

F (r) = r = (x, y, z) the surface equation z = 3(x^2 + y^2) z_x = 6x, z_y = 6y the normal vector n = (- z_x, - z_y, 1) = (- 6x, - 6y, 1)

Thus, flux ∫∫s F · dS is given as;

∫∫ <x, y, z> · <-z_x, -z_y, 1> dA

=∫∫ <x, y, 3x² + 3y²> · <-6x, -6y, 1>dA , since z = 3x² + 3y²

Thus, flux is;

= ∫∫ -3(x² + y²) dA.

Since the region of integration is bounded by x² + y² = 25, let's convert to polar coordinates as follows:

∫(θ = 0 to 2π) ∫(r = 0 to 5) -3r² (r·dr·dθ)

= 2π ∫(r = 0 to 5) -3r³ dr

= -(6/4)πr^4 {for r = 0 to 5}

= -(6/4)5⁴π - (6/4)0⁴π

= -937.5π

4 0
3 years ago
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