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erastova [34]
4 years ago
10

Helpppppppppp please

Mathematics
1 answer:
Advocard [28]4 years ago
4 0

Answer:

27ft³

Step-by-step explanation:

1 yard = 3 feet

1yard³ = 1 yard*1yard*1yard = 3feet*3feet*3feet

= 3³ feet³ = 27ft³

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vfiekz [6]

Answer:reflect across

Step-by-step explanation:

4 0
3 years ago
Please help me with this problem
Alexus [3.1K]
(a) It is leaking 18 liters per minute.

Explanation : From 15 minutes to 20 minutes, your starting point at 15 is 590 liters and at 20 you have exactly 500. Next you have 25 which is now at 410. So it's leaking 90 liters every five minutes, so of course dividing the two (90 ÷ 5) you get 18.

(a)² it increases for about the same time that it would decrease of course.

(b) The vat started at 860 liters before they started draining it.

Explanation : Well, all it takes is just working backwards, add 90 liters to the liters at 15 minutes and deduct five minutes from 15. Do this process until you arrive at 0. It's simple
7 0
4 years ago
Fred bought 7 games on clearance for $104.65. Each game was on sale for the same price. How much did each game cost? (Show your
NISA [10]

Answer:

Each game cost $14.95.

Step-by-step explanation:

104.65 = 7x

104.65/7 = x

14.95 = x

3 0
3 years ago
2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
Oksana_A [137]

Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
4 years ago
0.00000000001 convert number to scientific notation
miss Akunina [59]
The scientific notation is:

<u><em>1.0 x 10^-11</em></u>
8 0
4 years ago
Read 2 more answers
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