Question

Question 10 [10 points] The number of frogs in a pond increases continuously at a rate proportional to the number present. There are 150 frogs present at a given time and 530 present 4 hours later. (a) How many frogs will there be 10 hours later the initial time? (b) How long will it take for the population to reach 10000 frogs?

Answer 1

Answer:

a) 1325 frogs b)75.47 hours

Step-by-step explanation:

start = 150 frogs

after 4 hours = 530

1) figure out how many frogs per hour 530/4 = 132.5 frogs per hour

2) 10 hours after initial time * 132.5 frogs = 1325 frogs

3) Time to reach 10000 frogs is => 10000 / 132.5 = 75.47 hours