Question

The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how many bacteria will be present at the end of the 8th hour?

Answer 1

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$