Answer:
1 inch : 4 feet
Step-by-step explanation:
Size of the Mural is 42 feet long and 16 feet.
The original painting is 10½ inches long and 4 inches wide.
On the length
Length of Painting: Length of Mural
10½ inches: 42 feet
1 inch : 42/10½ feet
1 inch : 4 feet
On the Width
Width of Painting: Width of Mural
4 inch: 16 feet
1 inch : 16/4 feet
1 inch : 4 feet
The Scale of the Original Painting to the Mural is therefore:
1 inch : 4 feet
Answer:
<h2>y = 2</h2>
Step-by-step explanation:
Answer:
The orange one is the answer
Step-by-step explanation:
The easiest way to find the solution is to plug in one of the coordinates that is located in the shaded area into each equation. If the equations make sense, as they do in the orange option, you have your answer.
Hope this helps you!
Answer:
y≤ -1/4 - 7x/8
Step-by-step explanation:
Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
