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Lady_Fox [76]
2 years ago
9

30 more than the quotient of b and c

Mathematics
2 answers:
Aliun [14]2 years ago
8 0

Answer:

b/c+30

Step-by-step explanation:

prisoha [69]2 years ago
3 0
(B/C)+30
This is what I think it is. Have a good day
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Ava,Carter,Luke and their dad each mow a different section of their yard.Ava mow 1 /12 of the yard, Carter mow 2 /12 of the yard
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His dad mowed 5/12 of the yard
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Which of these characteristics do a rhombus and a rectangle always have in common?
lutik1710 [3]

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Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len
FromTheMoon [43]

Width of the miniature model = 3\frac{3}{4} inches

Length of the miniature model = 5\frac{1}{2} inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x

$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x

$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}

Do cross multiplication.

$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}

$\Rightarrow{\frac{15}{4}x =\frac{165}{2}

$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0
3 years ago
A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
Drupady [299]

Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

∵ The mass = 23.6 g

∵ The volume = 150 cm³

∴ The density = 23.6/150 = 59/375 ≅ 0.157 g/cm³

* The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

- By using cross multiplication

∴ The volume = 3.2/13.6 = 4/17 cm³

* The volume of the container is 4/17 ≅ 0.235 cm³

# The density of the iron is 4.9 g/cm³

- The beaker has a volume 250 ml

∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

7 0
3 years ago
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