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GCF is the greatest common factor of two or more numbers
To find it factorize the numbers and find their common factor, and choose the greatest one
Let us find the factors of 35
35 = 1 * 35
35 = 5 * 7
Then the factors of 35 are 1, 5, 7, 35
Let us find the factors of 25
25 = 1 * 25
25 = 5 * 5
Then the factors of 25 are 1, 5, 25
The common factors of 35 and 25 are 1, 5
The greatest is 5
So the GCF of 35 and 25 is 5
Given Mr. Engle’s total income, I = $52,000 and total expenses, E = $53,800, solving for average difference between income and expenses per month:
(I-E)/12 = ($52,000 - $53,800)/12
(I-E)/12 = - $1,800/12
(I-E)/12 = -$150
This means that Mr. Engle’s expenses exceed his income by an average of $150 each month in the said year.
You forgot to say what the question actually is !
But I've seen this problem before, in the last few days, here on Brainly.
I think the problem has three parts: 1). Solve the equation for 'a';
2). Solve it for 'b'; and 3). Solve it for 'c'.
I'll slog through that, and I'll try to explain what I'm doing clearly enough
so that eventually, you can do it on your own ... which is really the whole
idea behind this website.
1). Solve the equation for 'a'. That means you have to wind up with something
that says a = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract (b/c +1) from each side: D - b/c - 1 = a/c
Multiply each side by 'c' : <em>Dc - b - c = a</em>
========================
2). Solve the equation for 'b'. That means you have to wind up with something
that says b = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract (a/c +1) from each side: D - a/c - 1 = b/c
Multiply each side by 'c' : <em>Dc - a - c = b</em>
==========================
3). Solve the equation for 'c'. That means you have to wind up with
something that says c = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract 1 from each side: D - 1 = a/c + b/c
The two fractions on the right can be added/combined: D - 1 = (a + b) / c
Multiply each side by 'c' : c(D - 1) = (a + b)
Divide each side by (D - 1) : <em>c = (a + b) / (D - 1)</em>