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alina1380 [7]
4 years ago
14

Nala is designing a piece of jewelry made of wire that has the shape shown below. It consists of two sides of a square and three

-quarters of a circle. To the nearest tenth, what is the length of wire needed? Note that no wire is needed along the dashed line segment. (the curved part is three fourths the circumference)
(1) 14.1


(2) 18.4


(3) 20.1


(4) 24.8

Mathematics
1 answer:
SVEN [57.7K]4 years ago
6 0

Answer:

Option (3) is the answer.

Step-by-step explanation:

Given question is incomplete; find the complete question in the attachment.

Jewelry made by Nala is a composite figure having three fourth of a circle and two sides of a square.

Perimeter of the whole figure will give us the length of wire needed to design the jewelry.

Perimeter of three fourth of a circle P(circle) = \frac{3}{4}(2\pi r)

Here, r = radius

P(circle) = \frac{3\pi (3)}{2}

             = 14.14 cm

Perimeter of the complete (composite) figure = 14.14 + 3 + 3

                                                                            = 20.13

                                                                            ≈ 20.1 cm

Therefore, Option (3) is the answer.

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Answer:

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Step-by-step explanation:

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A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\

2. Note that

A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

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