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Andre45 [30]
4 years ago
13

On Friday, Andre biked 60 miles in 4 hours at a constant rate. On Saturday, he biked at a rate that was 4 mph slower. What was h

is rate on Saturday?
Mathematics
1 answer:
cricket20 [7]4 years ago
5 0
11 miles per hour

60/4

=15-4 = 11
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The graph shows the relationship between the number of granola bars and amount of calories per bar.
castortr0y [4]

part a y= x × 100

Step-by-step explanation:

1 bar is 100 calories so you would times it by 100 for every bar

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3rd question, I’m sorry guys but I was sick that’s why I didn’t attend school and the teacher said if I didn’t submit it by 5 ho
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Answer:

21.  ΔUYZ <u>Obtuse</u>

22. ΔBCD <u>Right or Rectangle</u>

23. ΔADB <u>Acute</u>

24. ΔUXZ <u>Acute</u>

25. ΔUWZ <u>Right or Rectangle</u>

26. ΔUXY <u>Equiangular and acute</u>

Step-by-step explanation:

We need to classify each triangle by its angles.

Acute: They have 3 acute angles (less than 90 degrees).

Rectangle: The inner angle A is straight (90 degrees) and the other 2 angles are sharp. The sides that form the right angle are called legs (c and b), the other side hypotenuse.

Obtuse: The inner angle A is obtuse (more than 90 degrees). The other 2 angles are acute.

ΔUYZ Obtuse  The inner angle Y is obtuse (more than 90°).

ΔBCD Right or Rectangle The inner angle C is straight (90°).

ΔADB Acute It has 3 acute angles (less than 90°).

ΔUXZ Acute  It has 3 acute angles (less than 90°).

ΔUWZ Right or Rectangle The inner angle W is straight (90°).

ΔUXY Equiangular and acute Which means all the inner angles are equal (60°).

3 0
3 years ago
Which statement would produce a tautology?<br> p q<br> p q<br> p p<br> q p
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Hello There!

I'm assuming it is p p.

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What is the gcf of the numerator and denominator of the rational expression
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Selection A is appropriate.
5 0
3 years ago
A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take
muminat

Answer:

The speed of jogger in uphills is 4 mile per hour  

And  The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill     (Du)  = 2 miles

The time taken by jogger in downhill       (Td)  = T  hour

The time taken by jogger in uphill            (Tu)  = T hour

Let The speed of jogger in uphills            (Su)  = x mph

So ,The speed of jogger in downhills      (Sd)  =( x + 6 ) mph

∵, Time = \frac{Distance}{Speed}

So, Tu = \frac{Du}{Su}

Or, T = \frac{2}{x}   h

And Td = \frac{Dd}{Sd}

Or,   T = \frac{5}{(x + 6)}  h

∵  Time duration of both is same

∴  \frac{2}{x} = \frac{5}{(x + 6)}

Or,  2 × (x + 6) = 5x

Or,  2x + 12 = 5x

So,    12 = 3x

∴       x = \frac{12}{3} = 4 mph

And  x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour  

And      The speed of jogger in downhills is 10 mile per hour   Answer

5 0
3 years ago
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