Divide the first equation by 2 and add the result to the second equation. This will eliminate x.
... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)
... 3y = -18 . . . . . collect terms
... y = -6 . . . . . . . divide by 3
Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.
... 2x +4(-6) = -12
... 2x = 12 . . . . . . . . add 24
... x = 6 . . . . . . . . . . divide by 2
The solution is (x, y) = (6, -6).
Answer:
8 students in each van ~ 22 in each bus
Step-by-step explanation:
- Equations:
8v + 8b = 240
4v + b = 54
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- Modify:
8v + 8b = 240
8v + 2b = 108
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- Subtract and solve for "b":
6b = 132
b = 22 (# of students in each bus)
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- Solve for "v":
4v + b = 54
4v + 22 = 54
4v = 32
v = 8 (# of students in each van)
on my calculator 48^1/5 equals 2.168943542
but out of a fraction 1/5 equals 0.2 ( they both equal the same thing)
2.168943542
Answer:
Side A is 4
Step-by-step explanation:
Answer:
x = 50
R = $2500
Step-by-step explanation:
Given in the question a quadratic equation,
−x² + 100x
To find the selling price, x, which will give highest revenue, y, we will find maximum value of parabola curve −x² + 100x
The value of -b/2a tells you the value x of the vertex of the function
−x² + 100x
here a = -1
b = 100
Selling price = -(100)/2(-1)
= 50
R = −(50)² + 100(50)
= 2500
