Given that ∠MQL = 180° and ∠XQR = 180°, which equation could be used to solve problems involving the relationships between ∠XQL
and ∠MQR?
A) (48 + 1b) = (54 − 1b)
B) (48 + 1b) + (54 − 1b) = 180
C) (54 − 1b) − (48 + 1b) = 180
D) (54 − 1b) − 180 = (48 + 1b)
2 answers:
Given
∠MQL = 180° and ∠XQR = 180°
Find out which equation be used to solve problems involving the relationships between ∠XQL and ∠MQR.
To proof
Vertically opposite angle
The angles opposite each other when two lines cross. They are always equal.
As shown in the diagram
∠XQL, ∠MQR are vertically opposite angle.
∠XQL = ∠MQR
(48 +1b) = (54 - 1b)
The problem used to solve problems involving the relationships between ∠XQL and ∠MQR is (48 +1b) = (54 - 1b).
option ( A) is correct.
Hence proved
The answer will be A which is (48+1b)=(54-1b). Hope it help!
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GIVEN
The following values are given:

SOLUTION
The z-score for the x values 9 and 14 can be calculated using the formula:

For x = 9:

For x = 14:

The probability can be calculated as follows:
![P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671](https://tex.z-dn.net/?f=P%289%5Cle%20x%5Cle14%29%3DPr%28-0.34The%20region%20that%20represents%20the%20solution%20is%20shown%20below%3A%3Cp%3ETherefore%2C%20the%20probability%20is%20given%20to%20be%3A%3C%2Fp%3E%5Btex%5DP%289%5Cle%20x%5Cle14%29%3D0.4671)
The probability is 0.4671.