Four batches should be the correct answer
Hello!
This is real simple!
So let's look at your first ordered pair, (-2,0)
-2 is the x-coordinate, 0 is the y-coordinate. 0 is the origin - or the center - of your graph. Don't put a point yet!
Next, -2 is to the left, so look for -2 on your graph (or count two to the left) Now put a point there. You have plotted (-2,0) on your graph!
Let's try another.
(0,4)
Look at 0 on your graph. The 4 is the y-coordinate, indicating that you'll go up on the y-axis.
Go up 4 on your y-axis
Put a point, you plotted (0,4)
One more?
(2,0)
x. y
Go to positive 2 on your x-axis (since it is the x-coordinate). Notice the y-coordinate is 0, you don't need to go up! Plot your point
You plotted (2,0)
I hope I helped. Please ask if you still need help.
Step-by-step explanation:
Hey there!
The coordinates of a triangle are;
- A (1,2)
- B (1,-2)
- C (-2,-2)
- Scale factor = -4 and centre at (0,0)
Now, We have;
P(x,y)----------- P'(kx, ky)
<u>Keep</u><u> </u><u>formula</u><u>;</u>
<u>A</u><u>(</u><u>1</u><u>,</u><u>2</u><u>)</u><u>----------</u><u> </u><u>A'</u><u>(</u><u>-4</u><u>×</u><u>1</u><u> </u><u>,</u><u>-4</u><u>×</u><u>2</u><u>)</u>
= A'(-4, -8)
B(1,-2)------------- B'(-4,8)
C(-2,-2)-------------C'(8,8)
[ <u>The</u><u> </u><u>A'</u><u> </u><u>should</u><u> </u><u>be</u><u> </u><u>kept</u><u> </u><u>in</u><u> </u><u>(</u><u>-4</u><u>,</u><u>-</u><u>8</u><u>)</u><u>.</u><u> </u><u>There</u><u> </u><u>was</u><u> </u><u>no</u><u> </u><u>place</u><u> </u><u>in</u><u> </u><u>this</u><u> </u><u>graph</u><u> </u><u>so</u><u>,</u><u> </u><u>i</u><u> </u><u>kept</u><u> </u><u>it</u><u> </u><u>just</u><u> </u><u>below</u><u> </u><u>-7</u><u>.</u><u> </u><u>Please</u><u> </u><u>while</u><u> </u><u>plotting</u><u> </u><u>remember</u><u> </u><u>to</u><u> </u><u>keep</u><u> </u><u>it</u><u> </u><u>on</u><u> </u><u>"</u><u>-8"</u><u>.</u><u>]</u>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Step-by-step explanation:
Look at the picture.
A' - The complement of a set is the set of all elements in the given universal set U that are not in A.
B - A - The set difference of sets A and B is the set of all elements in A that are not in B.
A ∩ B - The intersection of sets A and B is the set of all distinct elements that are in both A and B.
Answer:
A. f(-1) = -3, f(7) = 13
Step-by-step explanation:
✔️When input (n) = -1:
f(n) = 2n - 1
f(-1) = 2(-1) - 1
f(-1) = -2 - 1 = -3
✔️When input (n) = 7:
f(n) = 2n - 1
f(7) = 2(7) - 1
f(-1) = 14 - 1 = 13