Step 1 :
Equation at the end of step 1 :
15
((——•(m6))•(0-2m2))•4
10
Step 2 :
3
Simplify —
2
Equation at the end of step 2 :
3
((— • m6) • -2m2) • 4
2
Step 3 :
Equation at the end of step 3 :
3m6
(——— • -2m2) • 4
2
Step 4 :
Multiplying exponential expressions :
4.1 m6 multiplied by m2 = m(6 + 2) = m8
Canceling Out :
4.2 Canceling out 2 as it appears on both sides of the fraction line
Equation at the end of step 4 :
-3m8 • 4
Step 5 :
Final result :
-12m8
Hello :
tan²(θ) = 3.. equi : tan(θ) = √3 or tan(θ) = -√3
1 ) tan(θ) = √3
tan(θ) = tan(<span>π/3)
</span>θ = π/3 +kπ k in Z
2)tan(θ) = -√3
tan(θ) = tan(-π/3)
θ = -π/3 +kπ k in Z
Let the first odd integer = n
∴ The second <span>consecutive odd integer = n+2
∴ </span><span>The sum of the two integers = (n) + (n+2)
= 2n + 2
</span> The correct choice is option (D)
<span> D) 2n + 2
</span>
Answer:
−
311.44
Step-by-step explanation:
I'm not sure about my answer but i tried