Answer:
Yes, x-10 is an accurate expression. . . .
Hope that helps
Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
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Answer:
P(X<1200) is 0.8212
Step-by-step explanation:
Test statistic (z) = (X - mean)/sd
X is score of a tester = 1200
mean = 1497
sd = 322
z = (1200 - 1497)/322 = -297/322 = -0.92
The cumulative area of the test statistic is the probability that X<1200. The cumulative area is 0.8212.
Therefore, P(X<1200) = 0.8212
Answer:
Step-by-step explanation:
What is the question?
Amount of change = 5.5-3.1 = 2.4 inches
Percentage change = 2.4/3.1 ≈ 77.4% increase
Given :
A clerk is paid $45.25 per hours for 40 hours a week, 1.50 times the regular rate of overtime and double the rate for a holiday.
To Find :
How much does the clerk get if he works overtime for 5 hours and 2 hours on holidays.
Solution :
Amount from regular job = $ 45.25 × 40 = $1810 .
Amount from overtime = $ (45.25×1.5) × 5 = $339.375 .
Amount from holiday = $ (45.25×2) × 5 = $452.5 .
Total amount clerk will get is :
T = $( 1810 + 339.375 + 452.5 )
T = $2601.875
Hence, this is the required solution.
