Answer:
y
=
3
2
x
+
1
Explanation:
To find the slope
(
m
)
of the straight line that passes through two points
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
apply:
(
y
1
−
y
2
)
=
m
(
x
1
−
x
2
)
In this example our two points are
(
0
,
1
)
and
(
2
,
4
)
Hence:
(
1
−
4
)
=
m
(
0
−
2
)
−
3
=
−
2
m
→
m
=
3
2
The equation of a straight line in slope
(
m
)
and intercept
(
c
)
form is:
y
=
m
x
+
c
In this example:
y
=
3
2
x
+
c
Since the point
(
0
,
1
)
is on this line
→
1
=
0
+
c
Hence,
c
=
1
∴
y
=
3
2
x
+
1
is our required straight line.
Step-by-step explanation:
Answer: A(4,0) and B(-2.0)
Step-by-step explanation:
First, do (x-4),
Now, x-4=0, then subtract
X=4
Now x+2
X+2=0, then subtract
X=-2
3t square+4t+9t square+6t square
9t square+6t square+3t square+4t
18t square+4t
It's pretty clear what the pattern is - 2^(k-1) * (-1)^(k-1) would work backwards, but we have to work forwards to get lower in this case, so we could start at -3 (as long as we put the k-1 in absolute value to make sure it's not 1/8), so we could write it as ∑ (k=1, goes to 4) 2^(|k-4|)*(-1)^(k-4)
It doesn't matter for k-4 because 1/-1 and 1/1 are the same thing as -1 and 1 respectively
