Assume that the weights of spawning Chinook salmon in the Columbia river are normally distributed. You randomly catch and weigh
1 answer:
Answer: The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample = 31.2 pounds .
Step-by-step explanation:
The weights of spawning Chinook salmon in the Columbia river are normally distributed.
Given : The mean weight from your sample is 31.2 pounds with a standard deviation of 4.4 pounds.
The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample
i.e. is 31.2 pounds because the best point estimate for population mean is the sample mean. [in normal distribution]
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Y = -3x + 6
y - 6 = -3x
-1/3 y + 2 = x
z = x -3
z = -1/3 y + 2 -3 = -1/3 y - 1
set z = 0
-1/3 y = 1
y = -3
set y = 0
z = - 1
y - 6 = -3x
-1/3 y + 2 = x
z = x -3
z = -1/3 y + 2 -3 = -1/3 y - 1
set z = 0
-1/3 y = 1
y = -3
set y = 0
z = - 1
Answer:
The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data is
Step-by-step explanation:
Time (months) Views
0 50
2 313
4 1950
6 12,210
8 76,300
10 476,800
Slope =131.5
Slope =818.5
Since the slope is not same . So, it is not a linear relationship
Since the ratio between the consecutive outputs is same so, it is exponential relationship.
Formula :
Where a is the initial value = 50
b = rate of change = 6.25
The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data
So