Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Please explain your question more in depth next time
Answer:
48.06
Step-by-step explanation:
b^2+c^2=A^2
45+16=42.06
add the extra 6
Answer:
f(x) = 1-x^2
Step-by-step explanation:
The graph of f(x) is just shifted down 3 units
A shift down is a subtraction
f(x) = g(x) -3
= 4- x^2 -3
=1-x^2
Answer:
60
Step-by-step explanation:
