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tresset_1 [31]
3 years ago
15

G how many distinct ordered arrangements of the letters of the word boogaboo can be made?

Mathematics
1 answer:
REY [17]3 years ago
3 0
In the word "boogaboo", there are eight (8) letters while there are only four distinct letters. The number of distinct ordered arrangements can be calculated through the equation,

            n = 8!/(2!)(4!)

where there are 2 letter b's and 4 letter o's. The answer to this item is 840.

Answer: 840
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<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B2%7D%20%20-%204%20%20%5Cdiv%20%20%5Csqrt%7B3%7D%20%20-%202" id="TexFormula1" tit
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Multiply numerator and denominator of (4 - 3 sqrt(2))/(2 - sqrt(3)) by sqrt(3) + 2:
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