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tresset_1 [31]
3 years ago
15

G how many distinct ordered arrangements of the letters of the word boogaboo can be made?

Mathematics
1 answer:
REY [17]3 years ago
3 0
In the word "boogaboo", there are eight (8) letters while there are only four distinct letters. The number of distinct ordered arrangements can be calculated through the equation,

            n = 8!/(2!)(4!)

where there are 2 letter b's and 4 letter o's. The answer to this item is 840.

Answer: 840
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Answer:

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile, that is, the value of X when Z has a pvalue of 0.01. So X when Z = -2.325.

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4 0
3 years ago
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- pls comment & correct me if i did smth wrong :’)
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