Collecting pennies can either be a dependent or an independent events based on the scenario.
<h3>How to illustrate the information?</h3>
Events classified as independent do not depend on other events for their occurrence. For instance, if we toss a coin in the air and it lands on head, we can toss it again and this time it will land on tail.
A coin toss is an illustration of an autonomous occurrence. With each toss of the coin, there is an equal probability (0.5) of either heads or tails occurring, presuming that the coin is fair and can only land on heads or tails. It doesn't matter if the coin came up heads on the prior toss.
In conclusion, collecting pennies can either be a dependent or an independent events based on the scenario.
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Remark
The reason you are not getting many replies to this is an uncertainty about f(x). We do not know if you mean f(x) = 2/(x - 6) or f(x) = (2/x) - 6. We'll try it both ways.
First Way f(x) = 2/(x - 6)
f(x = y = 2/(x - 6) Interchange x and y
x = 2 / (y - 6) Multiply both sides by y - 6
x(y - 6) = 2 Divide by x
y - 6 = 2/x Add 6 to both sides.
y = 2/x + 6 Which is close to g(x) but it is not the same thing, even if you use x as a common denominator. That would give you
Second Way: f(x) = (2/x) - 6
f(x) = y = (2/x) - 6 Interchange x and y
x = (2/y) - 6 Add 6 to both sides
x + 6 = 2/y Multiply both sides by y
y(x + 6) = 2 Divide by sides by (x + 6)
y = 2/(x + 6)
Comment
These do not look anything alike so g(x) and f(x) are not inverses.
-1,4 I think so, good luck
The correct answer is the last option.
Since the coach is studying the two different groups, the results will be more meaningful if the groups are compared to one another as opposed to the players. It would also make more sense to study the mean (or average) of the points scored, rather than the standard deviation (which is essentially a measure of how spread out a set of numbers are).
