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8090 [49]
3 years ago
7

the total volume of a cube is 360 inches to the third power how do you write 2 different possible sets of diminsions for the cub

e
Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

If it's really a cube, then it can have only one set of dimensions.
Actually, only one dimension ... the length of every edge is the
same number.

The volume of a cube is the cube of its edge length.  So the
length of every edge is the cube root of its volume.

But the dimension can sometimes be written in different ways.

Volume = 360 inch³

Edge length =  ∛(360 inch³)

                    = ∛360  inches

                    =  3 ∛(13 and 1/3)  inches

                    =  4 ∛5.625  inches

                    =  5 ∛2.88    inches

                    =  6 ∛(1 and 2/3)  inches  .

Amiraneli [1.4K]3 years ago
5 0
Well,

Since it's a cube, there will only be one real dimension, and that will be the cube root of 360.

\sqrt[3]{360} = 2\sqrt[3]{45}\ inches

The only way to write different dimensions is to write using different units.

12 in. = 1 ft.

\frac{2\sqrt[3]{45}}{12} = \frac{\sqrt[3]{45}}{6}\ feet
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Two friends share 7 cookies equally .How many cookies does each friend get
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they would get 3 1/2

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Jay wants to make a box, with no lid (or top), out of a 10" x 6" rectangular piece of cardboard. If Jay cuts squares with dimens
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Answer:

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Step-by-step explanation:

Dimensions of rectangular piece of cardboard=10\times 6

According to question

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a.

Volume of box=l\times b\times h

Substitute the values in the formula

Volume of box=x(10-2x)(6-2x)

V(x)=x(10-2x)(6-2x)

b.Surface area of box=2(b+l)h+lb

Because the box has no lid

Substitute the values in the formula

Surface area of box=2(10-2x+6-2x)x+(10-2x)(6-2x)

Surface area of box=2(16-4x)x+60-20x-12x+4x^2

Surface area of box=32x-8x^2+60-32x+4x^2

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And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

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So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
3 years ago
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