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valentina_108 [34]
3 years ago
6

An investment of $1,000 is earning interest at the rate of 3.8% compounded daily over 3 years. Approximately how much interest i

s earned on the investment?
(PLEASE SHOW WORK)
a.
$892.26
b.
$1120.75
c.
$120.75
d.
$38.73
Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

c.  $120.75

Step-by-step explanation:

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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BEST ANSWER GETS BRAINLIEST!!!!!!!!
Ad libitum [116K]

Answer:

(x + 6, y + 0), 180° rotation, reflection over the x‐axis

Step-by-step explanation:

The answer can be found out simply , a trapezoid has its horizontal sides usually parallel meanwhile the vertical sides are not parallel.

The horizontal parallel sides are on the x-axis.

Reflection over y- axis would leave the trapezoid in a vertical position such that the trapezoid ABCD won't be carried on the transformed trapezoid as shown in figure.

So option 1 and 2 are removed.

Now, a 90 degree rotation would leave the trapezoid in a vertical position again so its not suitable again.

In,The final option (x + 6, y + 0), 180° rotation, reflection over the x‐axis, x+6 would allow the parallel sides to increase in value hence the trapezoid would increase in size,

180 degree rotation would leave the trapezoid in an opposite position and reflection over x-axis would bring it below the Original trapezoid. Hence, transformed trapezoid A`B`C`D` would carry original trapezoid ABCD onto itself

8 0
3 years ago
2. A dance floor is a square with an area of 1,444 FT(2). What are the dimensions of the dance floor?
svet-max [94.6K]

Answer:

The answer is C use a calculator

Step-by-step explanation:

not that hard lol

8 0
3 years ago
How do I find the integral<br> ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?
defon
\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1

(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1

\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow  \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2

\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3

\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}



4 0
3 years ago
What is the perimeter of the triangle?
lesya692 [45]

Answer:

Step-by-step explanation:

8,15,15 너 도넛

6 0
2 years ago
Find three consecutive odd integers such that 5 times the third is 94 than the second
IrinaK [193]
------------------------------------------------------------
Define the numbers
------------------------------------------------------------
First the first odd integer be x.
1st odd = x
2nd odd = x + 2
3rd odd = x + 4

------------------------------------------------------------
Form the equation and solve for x
------------------------------------------------------------
5(x + 4) - 94 = x + 2
5x + 20 - 94 = x + 2
5x - 74 = x + 2
5x - x = 2 + 74
4x = 76
x = 19

------------------------------------------------------------
Find the 3 consecutive integers
------------------------------------------------------------
1st = x = 19
2nd = x + 2 = 19 + 2 = 21
3rd = x + 4 = 19 + 4 = 23

------------------------------------------------------------
Answer: The 3 consecutive odd numbers are 19, 21 and 23
------------------------------------------------------------

3 0
3 years ago
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