All categories

2 years ago

Olga deposited $1,500 in a savings account that pays 7.5% interest,

1 answer:

4 0

Based on the question I generated the equation 1500(1.075^x). X being quarterly pays.
To solve the question i input 3 for X considering she hasnt been payed for the forth quarter.
The answer you get should be ~$1863.45

You might be interested in

Please help! (Photo attached) solve the missing elements for each problem. Use 3.14 for pi (doing steps backwards )

mixas84 [53]

The circumference of the circle is 94.25 inches
The area of the circle is 706.86 inches

7 0

2 years ago

Sean drank a slushy as fast as he could.

padilas [110]

D. 8 ml per second is the answer

6 0

2 years ago

Find x.<br> X=<br> 400<br> 8<br> Round to two decimals at each step of the problem.

svlad2 [7]

Answer:

6.71

Step-by-step explanation:

→ Find a triangle to use

Tan = Opposite ÷ Adjacent

→ Rearrange to make opposite the subject

Opposite = Tan × Adjacent

→ Substitute in the values

Opposite = Tan (40) × 8

→ Simplify

Opposite = 6.71

4 0

2 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

7x[(9+4)-(12-7)] please help me:(

lara [203]

Answer:

Step-by-step explanation:

7((9+4)-(12-7))

7(13-5)

7×8

3 0

3 years ago

Read 2 more answers