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taurus [48]
3 years ago
5

A pet store owner set the price of a bag of cat food at 50% above the cost. When it did not sell, the price was reduced by 20%,

to $12.00. What was the original cost?
Mathematics
2 answers:
algol [13]3 years ago
5 0

Answer:

60

Step-by-step explanation:

MA_775_DIABLO [31]3 years ago
5 0

Answer:

$10.

Step-by-step explanation:

Let x represent the original cost of bag of cat food.

We have been given that a pet store owner set the price of a bag of cat food at 50% above the cost. So the cost of cat food would be x plus 50% of x.

x+\frac{50}{100}*x\rightarrow x+0.5x=1.5x

We are further told that the price was reduced by 20%, when it did not sell. So price of cat food after reduction would be 1.5x minus 20 percent of 1.5x.

1.5x-(\frac{20}{100}\times 1.5x)

1.5x-(0.20\times 1.5x)

1.5x-(0.3x)

1.2x

Since price after reduction was $12, so we will equate 1.2x with 12 as:

1.2x=12

\frac{1.2x}{1.2}=\frac{12}{1.2}

x=10

Therefore, the original cost of cat food was $10.

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mash [69]

Answer:

A.   Undefined.

Step-by-step explanation:

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3 years ago
Regroup tens as hundreds
Andrew [12]
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Sladkaya [172]

Answer:

18360

Step-by-step explanation:

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Read 2 more answers
A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

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The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

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