Answer:
The phase shift:
1 unit to the right and 1 unit up
Step-by-step explanation:
∵ y = 1 + sin2(x - 1)
∴ y = 1 + sin(2x - 2)
∵ y = Sin(Bx - C) + D
∵ The vertical shift is D
∴ The horizontal shift is -C/B
∴ The vertical shift is 1 unit up
∴ The horizontal shift is --2/2 = 1 ⇒ 1 unite to the right
Anddd Similar traingles for one more time.
Here,
RQ/RP = RS/RT = QS/PT = 1/2
Using the values of QS and PT will give,
Therefore y= 46 units.
Answer is B .....hope this help
Problem 7: Correct
Problem 8: Correct
Problem 9: Correct
The steps are below if you are curious
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Problem 7
S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15
I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.
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Problem 8
First find y
y+116 = 180
y+116-116 = 180-116
y = 64
which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x
x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99
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Problem 9
With any polygon, the sum of the exterior angles is always 360 degrees
The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96
Box Plot has less variability in the data. We can determine this by the distances between the beginning of the data to the end (range) and the distances between lower quartile and the upper quartile (interquartile range).
Box #1
Range - 30
IQR - 15
Box #2
Range - approximately 23
IQR - approximately 9
Box #2 has less variation in the data because the distances between these 2 ranges are smaller meaning the data is closer together.
