Answer:
290m 1148 44 c dXsxcdfvb ehtwefgb fetths
Answer:
The Domain is all real values of x except x = 0 and x = -2.5.
Step-by-step explanation:
I am assuming that f(x) = 3/(x + 2).
(f o g)x is found by substituting 5/x for the x in 3/(x + 2).
(f o g) x = 3/ ( 5/x + 2)
= 3 / ( 5+2x) / x
= 3x / (5 + 2x).
When finding the domain you first check for values of x which make g(x) undefined then values of x which make (f o g)(x) undefined.
x = 0 makes g(x) = 5/0 so it is undefined and x = -2.5 makes g o f undefined also.
(a) Average time to get to school
Average time (minutes) = Summation of the two means = mean time to walk to bus stop + mean time for the bust to get to school = 8+20 = 28 minutes
(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)
Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes
(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
Now, P(x=30) = P(Z=-0.45) = 0.3264
Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%
With actual average time to walk to the bus stop being 10 minutes;
(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes
(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.
(f) Probability that it will take more than 30 minutes to get to school
Z(x=30) = (mean - 30)/Sd = (30-30)/4.47 = 0/4.47 = 0
From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
Answer:
C, D, and E are correct
Step-by-step explanation:
p(2)= 1/6; p(3)= 1/6; p(4)= 1/6; 1/6=1/6=1/6
p(1)= 3/6; 3/6=1/2
p(4) = 1/6; There are six sections and one section is labeled<em> '4' </em>
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Hope this helped! ;p
