This is vague. Any dimensions that make a triangle can make more than one, just draw another right next to it. What's really being asked is which dimensions can make more than one non-congruent triangle.
<span>A. Three angles measuring 75°,45°, and 60°.
That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions. TRUE
<span>B. 3 sides measuring 7, 10, 12?
</span>Three sides determine the triangles size and shape uniquely; FALSE
<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>
40+50+60=150, no such triangle exists. FALSE
<em>D. 3 sides measuring 3,4,and 5</em>
Again, three sides uniquely determine a triangle's size and shape; FALSE
</span>
The formula for midpoint is
(
, 
)
Look at the image below to see the line segment of Estefani's (A), Jasmin's (M), and Preston's (B) houses. Keep in mind that the segment shown below is not accurate in regards to how the line segment formed by Estefani's, Jasmin's, and Preston's houses. It is simply there so you can picture the segment better.
In this case:
^^^Plug in these number into the formula given above...
(
, 
)
To find what x is (a coordinate of Preston's house) you must take the x-value part of the midpoint equation () and set it equal to the x-value of the midpoint (-5). Then you must solve for x:
= -5
3 + x = -5 * 2
3 + x = -10
x = -10 - 3
x = -13
To find what y is (a coordinate of Preston's house) you must take the y-value part of the midpoint equation() and set it equal to the y-value of the midpoint (3). Then you must solve for y:
= 3
-2 + y = 3 * 2
-2 + y = 6
y = 6 + 2
y = 8
The coordinate of Preston's house is:
(-13, 8)
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
2
A)-7y^3-3y^2-2y-8
B)-7x^3y^3-12x^2y^2-xy
C)2xy^3+3xy^2-5
3
A)14x^2
B)15a^2+30ab
Step-by-step explanation:
a. vertical angles are congruent
b. congruence of angles is transitive
c. if two lines are cut by a transversal such that alternate interior angles are congruent, then the lines are parallel
