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bonufazy [111]
3 years ago
9

The sales tax in Buffalo is 8.75%. How much would someone have to pay for a shirt with a price of $24.99

Mathematics
1 answer:
olga_2 [115]3 years ago
8 0
Anything can be done right
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Find the x-intercept for the line represented by this equation.
k0ka [10]
3(0) = 2x + 6
( 0 = 2x + 6 ) - 6
( -6 = 2x ) /2
x = -3
The answer is B. (-3, 0).
3 0
3 years ago
Show Your Work<br> Please help I’ll mark brainliest
fgiga [73]

Answer:

(c)

Step-by-step explanation:

3+2+4 = 9,  4+2= 6- 3= 3

3 0
3 years ago
HELP ASAP
denis-greek [22]
A) I included a graph, look below.

B)

Input the y in x = y + 3.

x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0

Input that x value in y = -4x - 3

y = -4(0) - 3
y = 0 - 3
y = -3

(0, -3)

C)

Convert both equations to Standard Form.

x = y + 3
Subtract y from both sides.
x - y = 3

y = -4x - 3
Add 4x to both sides.
4x + y = -3

Add the equations together.

4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0

Input that into one of the original equations.

0 = y + 3
Subtract 3 from both sides.
-3 = y

(0, -3)

7 0
3 years ago
Select the two equivalent expressions.
Allushta [10]

Answer:

B. and D.

B. 10m+3m+m+10+6=4m+16

D. 4(m+4)=4m+16

6 0
2 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
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