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Nadya [2.5K]
3 years ago
12

Help asap!!!!!!!!!! Properties of exponents Simplify

Mathematics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

C) 4a^{6}b

Step-by-step explanation:

\frac{(4b^{3} 3a^{4}b^{2})}{3a^{-2} b^{4}} Copy the original equation

\frac{12a^{6}b^{5}}{3b^{4} } Combine like terms

\frac{12a^{6}b}{3} Simplify the b, then divide by 3

4a^{6}b

If this answer is correct, please make me Brainliest!

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Step-by-step explanation:

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Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)
sukhopar [10]

Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

y=1+4\sin(t)

Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

Subtract 2 on both sides:

x-2=-3\cos(t)

Divide both sides by -3:

\frac{x-2}{-3}=\cos(t)

Now time for the second equation, y=1+4\sin(t).

Subtract 1 on both sides:

y-1=4\sin(t)

Divide both sides by 4:

\frac{y-1}{4}=\sin(t)

Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

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Answer:

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Step-by-step explanation:

so f(4) means x = 4.

The new equation is

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Then solve

F = 9.25

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Answer:

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Step-by-step explanation:

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