Complementary angles ⇒ the angles add up to 90°
∠A and ∠B are complementary ⇒ ∠A + ∠B = 90°
∠A + ∠B = 90°
Plug in the values for ∠A and ∠B:
(3x - 8) + (5x + 10) = 90
Open the brackets:
3x - 8 + 5x + 10 = 90
Combine like terms:
8x + 2 = 90
Subtract 2 from both sides:
8x = 88
Divide both sides by 8:
x = 11
Answer: x = 11
The line has a positive slope. Let's look at all the slopes:
1) -3
2) -3
3) 3
4)3
Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.
The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.
1) y = -3/2x - 5/2
2) y = -3/2x + 5/2
We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.
The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.
I think it’s 3 I’m not sure
Answer:
a. y = 2/5x + 1/5
Step-by-step explanation:
In point-slope form, the equation of a line with slope m through point (h, k) can be written
y = m(x -h) +k
Then a line with slope 2/5 through the point (-3, -1) will have point-slope equation ...
y = (2/5)(x +3) -1
This can be simplified to the desired form:
y = 2/5x +6/5 -1 . . . . . . eliminate parentheses; next, collect terms
y = 2/5x + 1/5
12 oak boards
60 maple boards
hope this is helpful