The equation of the directrix x^2+16x=8y-16
1 answer:
The coefficient of y is 8, which is 4p, so p=2. That is the distance the directrix is below the vertex. The directrix is below the vertex because the parabola opens upward.
The vertex can be found by completing the square.
x^2 +16x +64 = 8y -16 +64
(1/8)(x +8)^2 -6 = y +6
The vertex is (-8, -6), so the directrix is ...
y = -8
The vertex can be found by completing the square.
x^2 +16x +64 = 8y -16 +64
(1/8)(x +8)^2 -6 = y +6
The vertex is (-8, -6), so the directrix is ...
y = -8
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