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3 years ago

The numeraiders won 7 games, lost 9 games and tied 2 games. What percent of the games did they win?

Mathematics

2 answers:

rewona [7]3 years ago

7 0

Answer:

39% of the games they won

Step-by-step explanation:

7+9+2=18

so there were 18 games in total and they won 7 of those games so they won 7/18 of the games.

You divide 7/18 and get 0.388888... you would round to the nearest hundredth place and get 0.39

To change a decimal to a percent you multiply by 100 and get 38%

bulgar [2K]3 years ago

6 0

Answer:

0.39%

Step-by-step explanation:

7+9+2= 18

7 divided by 18 and you'll get 0.38%. If you round it up it's 0.39%.

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How do i solve 12×+9=10×1

s2008m [1.1K]

Answer:

Step-by-step explanation:

Unfortunately, your " 12×+9=10×1 " can be interpreted in more than one way. The symbol " × " should be used ONLY to indicate multiplication. Thus, " 12× " reads as ' 12x.' Then we have: 12x + 9 = 10. Unsure of what you meant by " 10×1". So I will treat your "10×1" as simply '10.'

Then we have 12x + 9 = 10, which reduces to 12x = 1 if we subtract 9 from both sides.

12x = 1 yields x = 1/12.

If this is not the result you expected, please go back to the original problem and share it as accurately as you can.

6 0

3 years ago

Sheleah and her family are planning a trip from Los Angeles, California to Melbourne, Australia. While booking her family's plan

lina2011 [118]

Positive because when I looked at the graph, the scattered plots are increasing up.

3 0

3 years ago

Suppose the population of a certain city is 5289 thousand. It is expected to decrease to 4530 thousand in 50 years. Find the per

Tcecarenko [31]

Answer:

14.4% decrease

Step-by-step explanation:

Here is the formula for finding the percentage of decrease:

(starting value - final value) / starting value * 100.

So for your question,

$\frac{5289-4530}{5289} =.0144\\.0144 * 100 = 14.4\\$ /

There was a 14.4% decrease within 50 years.

5 0

3 years ago

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$