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EleoNora [17]
3 years ago
15

Help me on this one please also do it the same way for....28/50....3/4 please!

Mathematics
2 answers:
egoroff_w [7]3 years ago
4 0
17/25(4/4)=68/100 decimal
Percent 17/25= 68%
yaroslaw [1]3 years ago
3 0
Ok for percent it is 68% and for decimal it is .68. Hope this can help!
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saul85 [17]

Answer:

We conclude that political science classes require less writing time than history classes at 0.01 level of significance.

Step-by-step explanation:

We are given that the 55 randomly selected political science classes assigned an average of 16.3 pages of essay writing for the course. The standard deviation for these 55 classes was 4.8 pages.

The 54 randomly selected history classes assigned an average of 18.9 pages of essay writing for the course. The standard deviation for these 54 classes was 5 pages.

<em>Let </em>\mu_1<em> = </em><u><em>average writing time required by political science classes.</em></u>

<em />\mu_2<em> = </em><u><em>average writing time required by history classes.</em></u>

So, Null Hypothesis, H_0 : \mu_1\geq\mu_2      {means that political science classes require more or equal writing time than history classes}

Alternate Hypothesis, H_A : \mu_1      {means that political science classes require less writing time than history classes}

The test statistics that would be used here <u>Two-sample t test statistics</u> as we don't know about the population standard deviation;

                     T.S. = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }   ~ t__n_1_-_n_2_-_2

where, \bar X_1 = sample average pages of essay writing for political science classes = 16.3 pages

\bar X_2 = sample average pages of essay writing for history classes = 18.9 pages

s_1 = sample standard deviation for political science classes = 4.8 pages

s_2 = sample standard deviation for history classes = 5 pages

n_1 = sample of political science classes = 55

n_2 = sample of history classes = 54

Also,  s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }  =  \sqrt{\frac{(55-1)\times 4.8^{2}+(54-1)\times 5^{2}  }{55+54-2} } = 4.90

So, <u><em>test statistics</em></u>  =  \frac{(16.3-18.9)-(0)}{4.9 \sqrt{\frac{1}{55}+\frac{1}{54}  } }  ~ t_1_0_7

                               =  -2.77

The value of t test statistics is -2.77.

<u>Now, at 0.01 significance level the t table gives critical value of -2.365 at 107 degree of freedom for left-tailed test.</u>

<em>Since our test statistics is less than the critical value of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

<em />

Therefore, we conclude that political science classes require less writing time than history classes.

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I believe the length is 18 and the width is 3. 
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A restaurant decides to test their oven's thermostat to see if it is working properly, that is, if the actual temperature inside
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Step-by-step explanation:

Previous concepts

Parameter represent a property of a population and is calculated with the information of all the populatio. Some examples are the population mean and deviation \mu,\sigma

Statistic represent a propoerty of a sample and are used used in order to describe the population parameters, since represent estimators of the real parameters.

Solution to the problem

For this case we have information from a sample of n =20 times of temperatures of the oven

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