Please refer to the figure attached for the diagram of this problem.
Steps needed to find the width of the field (CD):
First, we should note that angle d would be equal to 27 degrees because there are two parallel lines that are cut by a transversal. Furthermore, angle a would be equal to 5 degrees since we just need to subtract 27 from 32.
We then subtract 27 and 5 from 180 to get angle c.
. Angle c is therefore 148 degrees.
Next, we need to find angle e which is just the supplementary of angle c. Angle e therefore measures
degrees.
For the next step we use sine law to find the length of segment AC:
Lastly, we need to utilize the sine law again to find the length of segment CD or the width of the field:
ANSWER: The width of the field is 290 ft.
Steps needed to find the width of the field (CD):
First, we should note that angle d would be equal to 27 degrees because there are two parallel lines that are cut by a transversal. Furthermore, angle a would be equal to 5 degrees since we just need to subtract 27 from 32.
We then subtract 27 and 5 from 180 to get angle c.
Next, we need to find angle e which is just the supplementary of angle c. Angle e therefore measures
For the next step we use sine law to find the length of segment AC:
Lastly, we need to utilize the sine law again to find the length of segment CD or the width of the field:
ANSWER: The width of the field is 290 ft.
